This is a tricky
Question, if I create 2 interface with
same method name, and implement both in one class. Now if create object of this
derived class, which method it will pick-up/Execute at run time.
To test this need to
create 2 interface with same method Name.
interface
IFace1
{
void GetFaceDetails();
}
interface
IFace2
{
void GetFaceDetails();
}
Now create a class
to implement both interfaces
public class DerivedClass : IFace1, IFace2
{
public DerivedClass()
{
Console.WriteLine(" Constructor Called. ");
}
void IFace1.GetFaceDetails()
{
Console.WriteLine(" IFace1.GetFaceDetails ");
}
void IFace2.GetFaceDetails()
{
Console.WriteLine(" IFace2.GetFaceDetails ");
}
}
Now to use this if I
create an object of IFace1
then It will call IFace1.GetFaceDetails
Method.
IFace1 obj1 = new DerivedClass();
obj1.GetFaceDetails();
So it will print
" IFace1.GetFaceDetails
"
Similarly if I create an object of IFace2 then It will call IFace2.GetFaceDetails Method.
IFace2 obj2 = new DerivedClass();
obj2.GetFaceDetails();
So it will print
" IFace2.GetFaceDetails
"
Now what if I create
an object of DerivedClass itself.
DerivedClass obj = new DerivedClass();
obj.GetFaceDetails();
In above code it
will show a compiler error that GetFaceDetails Method doesn’t exists in
DerivedClass. So it will not execute at all. Or you will have to create another
method with same name in class, and compiler will pick that method in
execution.
